From c31a91230d48f4ed35ebd812d83a661f06f401e1 Mon Sep 17 00:00:00 2001
From: wm4 <wm4@nowhere>
Date: Sun, 24 Aug 2014 12:41:07 +0200
Subject: demux: avoid unnecessary wakeups

If a packet is appended to a stream, and there were already packets
queued, nothing about the state changed, as far as the user (i.e. the
player) is concerned. Thus no wakeup is needed.

The pthread_cond_signal() call following this is not interesting - it
will simply be a NOP if there are actually no waiters.
---
 demux/demux.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/demux/demux.c b/demux/demux.c
index bb9363815e..f27b8d1855 100644
--- a/demux/demux.c
+++ b/demux/demux.c
@@ -318,7 +318,7 @@ int demux_add_packet(struct sh_stream *stream, demux_packet_t *dp)
            "[num=%zd size=%zd]\n", stream_type_name(stream->type),
            dp->len, dp->pts, dp->dts, dp->pos, ds->packs, ds->bytes);
 
-    if (ds->in->wakeup_cb)
+    if (ds->in->wakeup_cb && !ds->head->next)
         ds->in->wakeup_cb(ds->in->wakeup_cb_ctx);
     pthread_cond_signal(&in->wakeup);
     pthread_mutex_unlock(&in->lock);
-- 
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